80x^2-42x-5=0

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Solution for 80x^2-42x-5=0 equation:


Simplifying
80x2 + -42x + -5 = 0

Reorder the terms:
-5 + -42x + 80x2 = 0

Solving
-5 + -42x + 80x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(-1 + -10x)(5 + -8x) = 0

Subproblem 1

Set the factor '(-1 + -10x)' equal to zero and attempt to solve: Simplifying -1 + -10x = 0 Solving -1 + -10x = 0 Move all terms containing x to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + -10x = 0 + 1 Combine like terms: -1 + 1 = 0 0 + -10x = 0 + 1 -10x = 0 + 1 Combine like terms: 0 + 1 = 1 -10x = 1 Divide each side by '-10'. x = -0.1 Simplifying x = -0.1

Subproblem 2

Set the factor '(5 + -8x)' equal to zero and attempt to solve: Simplifying 5 + -8x = 0 Solving 5 + -8x = 0 Move all terms containing x to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -8x = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -8x = 0 + -5 -8x = 0 + -5 Combine like terms: 0 + -5 = -5 -8x = -5 Divide each side by '-8'. x = 0.625 Simplifying x = 0.625

Solution

x = {-0.1, 0.625}

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